| ⇦ | 
| ⇨ |
If particles are moving with same velocity, then maximum de Broglie wavelength will be for
Options
(a) Neutron
(b) Proton
(c) α-particle
(d) β-particle
Correct Answer:
β-particle
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A bar magnet with magnetic moment 2.5×10³ JT⁻¹ is rotating in horizontal plane
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- Frequency of stretched string will increase by
- The current in the windings of a toroid is 2.0 A. There are 400 turns
- The current in a conductor varies with time t as I=2t+3t² Where I is in amperes
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bar magnet with magnetic moment 2.5×10³ JT⁻¹ is rotating in horizontal plane
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- Frequency of stretched string will increase by
- The current in the windings of a toroid is 2.0 A. There are 400 turns
- The current in a conductor varies with time t as I=2t+3t² Where I is in amperes
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply