| ⇦ | 
| ⇨ |
If Nₐ is Avagadro number then number of valence electrons in 4.2g of nitride ions (N³⁻) is
Options
(a) 2.4 Nₐ
(b) 4.2 Nₐ
(c) 1.6 Nₐ
(d) 3.2 Nₐ
Correct Answer:
2.4 Nₐ
Explanation:
At weight of nitrogen= 14
No of moles of nitride ion = 4.2/14 = 0.3 mol
= 0.3 x Nₐ nitride ions
One N³⁻ ion contains 8 valence electrons. 5 + 3 due to charge.
Valence electrons = 8 x 0.3 Nₐ = 2.4 Nₐ
Related Questions: - Petroleum is a mixture of
- IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹
- For isothermal change in the case of an ideal gas
- Aniline is separated from aniline-water mixture by
- The values of heat of formation of SO₂ and SO₃ are -298.2 kJ and -98.2 kJ.
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Petroleum is a mixture of
- IF the bond energies of H – H , Br – Br and H – Br are 433 , 192 and 364 kJ mol⁻¹
- For isothermal change in the case of an ideal gas
- Aniline is separated from aniline-water mixture by
- The values of heat of formation of SO₂ and SO₃ are -298.2 kJ and -98.2 kJ.
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply