⇦ | ⇨ |
If Nₐ is Avagadro number then number of valence electrons in 4.2g of nitride ions (N³⁻) is
Options
(a) 2.4 Nₐ
(b) 4.2 Nₐ
(c) 1.6 Nₐ
(d) 3.2 Nₐ
Correct Answer:
2.4 Nₐ
Explanation:
At weight of nitrogen= 14
No of moles of nitride ion = 4.2/14 = 0.3 mol
= 0.3 x Nₐ nitride ions
One N³⁻ ion contains 8 valence electrons. 5 + 3 due to charge.
Valence electrons = 8 x 0.3 Nₐ = 2.4 Nₐ
Related Questions: - Which one of the elements has the highest ionisation energy?
- A particular solid is very hard and has a very high melting point. In solid
- The strongest conjugate base is
- The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy
- Which of the following is not a common component of Photochemical Smong
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the elements has the highest ionisation energy?
- A particular solid is very hard and has a very high melting point. In solid
- The strongest conjugate base is
- The energy of second Bhor orbit of the hydrogen atom is -328 kJ mol⁻¹, hence the enregy
- Which of the following is not a common component of Photochemical Smong
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply