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If Nₐ is Avagadro number then number of valence electrons in 4.2g of nitride ions (N³⁻) is
Options
(a) 2.4 Nₐ
(b) 4.2 Nₐ
(c) 1.6 Nₐ
(d) 3.2 Nₐ
Correct Answer:
2.4 Nₐ
Explanation:
At weight of nitrogen= 14
No of moles of nitride ion = 4.2/14 = 0.3 mol
= 0.3 x Nₐ nitride ions
One N³⁻ ion contains 8 valence electrons. 5 + 3 due to charge.
Valence electrons = 8 x 0.3 Nₐ = 2.4 Nₐ
Related Questions: - In which of the following reaction Kp > Kc
- The oxidation number of xenon in XeOF₂ is
- Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
- The nucleic acid base having two possible binding sites is
- In which of the following acid – base titration,pH is greater than 8
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In which of the following reaction Kp > Kc
- The oxidation number of xenon in XeOF₂ is
- Solution of 0.1 N NH₄OH and 0.1 N NH₄Cl has pH 9.25 . Then fine out pKb of NH₄OH
- The nucleic acid base having two possible binding sites is
- In which of the following acid – base titration,pH is greater than 8
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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