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If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton and neutron respectively in units of u (1u = 931.5 MeV/c) and BE represents its bonding energy in MeV, then
Options
(a) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²
(b) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE
(c) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE
(d) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE/c²
Correct Answer:
M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²
Explanation:
Mass defect = ZMₚ + (A – Z)Mₙ – M(A – Z)
or, B.E. / c² = ZMₚ + (A – Z)Mₙ – M(A – Z)
M(A – Z) = ZMₚ + (A – Z)Mₙ – B.E. / c²
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uniform wire of resistance 9Ω is joined end-to-end to form a circle. Then
- Radii of curvature of a converging lens are in the rato 1:2. Its focal length
- Magnetism of a magnet is due to
- A particle moving in a straight line with uniform acceleration is observed
- A body of mass (4m) is lying in x-y plane at rest. It suddenly explodes into three
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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