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If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton and neutron respectively in units of u (1u = 931.5 MeV/c) and BE represents its bonding energy in MeV, then
Options
(a) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²
(b) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE
(c) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE
(d) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE/c²
Correct Answer:
M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²
Explanation:
Mass defect = ZMₚ + (A – Z)Mₙ – M(A – Z)
or, B.E. / c² = ZMₚ + (A – Z)Mₙ – M(A – Z)
M(A – Z) = ZMₚ + (A – Z)Mₙ – B.E. / c²
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A polarised light of intensity I₀ is passed through another polariser whose pass axis
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
- An electron of mass m and a photon have same energy E. The ratio of de-Broglie
- A car moving with a velocity of 36 km/hr crosses a siren of frequency 500 Hz.
- A carnot’s engine operates with source at 127° C and sink at 27°C
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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