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If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton and neutron respectively in units of u (1u = 931.5 MeV/c) and BE represents its bonding energy in MeV, then
Options
(a) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²
(b) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE
(c) M(A, Z) = ZMₚ + (A – Z)Mₙ – BE
(d) M(A, Z) = ZMₚ + (A – Z)Mₙ + BE/c²
Correct Answer:
M(A, Z) = ZMₚ + (A – Z)Mₙ – BE/c²
Explanation:
Mass defect = ZMₚ + (A – Z)Mₙ – M(A – Z)
or, B.E. / c² = ZMₚ + (A – Z)Mₙ – M(A – Z)
M(A – Z) = ZMₚ + (A – Z)Mₙ – B.E. / c²
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A spherical drop of capacitance 1μF is broken into eight drops of equal radius.
- What will be the ratio of the distance moved by a freely falling body from rest in 4th
- Which wavelengths of sun is used finally as electric energy?
- The length of second pendulum is 1 m on earth. If mass and diameter
- A wooden stick 2 m long is floating on the surface of water. The surface tension
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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