⇦ | ![]() | ⇨ |
If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A in 2×10⁻³ s, then the coefficient of self-induction is
Options
(a) 2×10⁻³ H
(b) 10⁻³ H
(c) 0.5×10⁻³ H
(d) 4×10⁻³H
Correct Answer:
2×10⁻³ H
Explanation:
Induced emf, e = 2 V
i₁ = 8 A, i₂ = 6 A
∆t = 2 × 10⁻³ s
Coefficient of self-induction, L = e / (∆i/∆t)
= -2 / [(6-2) / 2 × 10⁻³]
= (-2 × 2 × 10⁻³) / -2
= 2 × 10⁻³ H
Related Questions:
- A charged particle with a velocity 2×10³ ms⁻¹ passes undeflected through electric field
- In a series resonant LCR circuit, the voltage across R is 100 volts and R =1kΩ
- The electric vector vibration of an electromagnetic wave is given by
- A condenser of capacity C is charged to a potential difference of V₁. The plates
- The temperature of a body falls from 50⁰C to 40⁰C in 10 minute. If the temperature
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply