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If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A in 2×10⁻³ s, then the coefficient of self-induction is
Options
(a) 2×10⁻³ H
(b) 10⁻³ H
(c) 0.5×10⁻³ H
(d) 4×10⁻³H
Correct Answer:
2×10⁻³ H
Explanation:
Induced emf, e = 2 V
i₁ = 8 A, i₂ = 6 A
∆t = 2 × 10⁻³ s
Coefficient of self-induction, L = e / (∆i/∆t)
= -2 / [(6-2) / 2 × 10⁻³]
= (-2 × 2 × 10⁻³) / -2
= 2 × 10⁻³ H
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Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The unit of permitivity of free space, ε₀ is
- The half-life period of a radio-active element X is same as the mean life time
- In an LCR series A.C circuit, the voltage across each of the components, L, C and R is 50V
- A uniform wire of resistance 9Ω is joined end-to-end to form a circle. Then
- If alternating source of primary coil on transformer is replaced by a Laclanche cell
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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