| ⇦ | 
| ⇨ |
If emf induced in a coil is 2 V by changing the current in it from 8 A to 6 A in 2×10⁻³ s, then the coefficient of self-induction is
Options
(a) 2×10⁻³ H
(b) 10⁻³ H
(c) 0.5×10⁻³ H
(d) 4×10⁻³H
Correct Answer:
2×10⁻³ H
Explanation:
Induced emf, e = 2 V
i₁ = 8 A, i₂ = 6 A
∆t = 2 × 10⁻³ s
Coefficient of self-induction, L = e / (∆i/∆t)
= -2 / [(6-2) / 2 × 10⁻³]
= (-2 × 2 × 10⁻³) / -2
= 2 × 10⁻³ H
Related Questions: - The net electric force on a charge of +3μC at the mid-point on the line joining two
- Which phenomenon best supports the theory that matter has a wave nature?
- One coolie takes 1 minute to raise a suitcase through a height of 2 m
- In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
- One milligram of matter on convertion into energy will give
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The net electric force on a charge of +3μC at the mid-point on the line joining two
- Which phenomenon best supports the theory that matter has a wave nature?
- One coolie takes 1 minute to raise a suitcase through a height of 2 m
- In a given process on an ideal gas, dW=0 and dQ<0. Then for the gas
- One milligram of matter on convertion into energy will give
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply