| ⇦ | 
| ⇨ |
If a compound, on analysis was found to contain C=18.5% ,H=1.55%, Cl=55.04% and O=24.81%, then its empirical formula is
Options
(a) C₂H₂OCl
(b) CH₂ClO
(c) CHClO
(d) ClCH₂O
Correct Answer:
CHClO
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Pyruvic acid is obtained by
- The Grignard reagent, on reaction with acetone forms
- The trivial names of propanone and 3-methyl-2-butanone are
- Mg and Li are similar in their properties due to
- Mg is present in
Topics: Basic Principles of Organic Chemistry
(124)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pyruvic acid is obtained by
- The Grignard reagent, on reaction with acetone forms
- The trivial names of propanone and 3-methyl-2-butanone are
- Mg and Li are similar in their properties due to
- Mg is present in
Topics: Basic Principles of Organic Chemistry (124)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply