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If a compound, on analysis was found to contain C=18.5% ,H=1.55%, Cl=55.04% and O=24.81%, then its empirical formula is
Options
(a) C₂H₂OCl
(b) CH₂ClO
(c) CHClO
(d) ClCH₂O
Correct Answer:
CHClO
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Oxidation number of carbon in CH₂Cl₂ is
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Topics: Basic Principles of Organic Chemistry
(124)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Oxidation number of carbon in CH₂Cl₂ is
- The molecular weight of a gas is 45. Its density at STP is
- 20 g of a non-volatile solute is added to 500 g of solvent. Freezing point
- How many unpaired electrons are present in ground state for Fe²⁺(Z=26)
- Which of the following is the lightest metal
Topics: Basic Principles of Organic Chemistry (124)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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