| ⇦ |
| ⇨ |
If a compound, on analysis was found to contain C=18.5% ,H=1.55%, Cl=55.04% and O=24.81%, then its empirical formula is
Options
(a) C₂H₂OCl
(b) CH₂ClO
(c) CHClO
(d) ClCH₂O
Correct Answer:
CHClO
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The raw materials for the commercial manufacture of DDT are
- Maximum number of electrons in a subshell of an atom is determined
- Which of the following statements is correct
- Which of the following is not an organometallic compound
- An aqueous solution of CoCl₂ on addition of excess of concentration HCl
Topics: Basic Principles of Organic Chemistry
(124)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The raw materials for the commercial manufacture of DDT are
- Maximum number of electrons in a subshell of an atom is determined
- Which of the following statements is correct
- Which of the following is not an organometallic compound
- An aqueous solution of CoCl₂ on addition of excess of concentration HCl
Topics: Basic Principles of Organic Chemistry (124)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply