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If a body is rolling on the surface, its total energy will be
Options
(a)(1/2) mv² – (Gm₁m₂/R)
(b) (1/2) mv² + (1/2) Iω²
(c) (1/2) mv² – (1/2) mR²ω²
(d) None
Correct Answer:
(1/2) mv² + (1/2) Iω²
Explanation:
Total energy = P.E. + K.E. of (linear motion + Rotation)
= 0 + (1/2) mv² + (1/2) Iω²
Total energy = (1/2) mv² + (1/2) Iω².
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- A ball is dropped from a high rise platform at t = 0 starting from rest
- The wheel of a car is rotating at the rate of 1200 rev/min. On pressing
- Colours appear on a thin soap film and soap bubbles due to the phenomenon of
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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