| ⇦ | 
| ⇨ |
If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
Options
(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032
Correct Answer:
0.0164
Explanation:
Here μᵥ=1.5230and μʀ=1.5145
Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187
Now, dispersive power, ω is given by,
ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164
Related Questions: - The distance travelled by an object along a straight line in time t is given by
- Two point objects of masses 1.5 g and 2.5 g respectively are at a distance of 16 cm
- Fusion reaction takes place at high temperature because
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
- In a n-p-n transistor about 10¹⁰ electrons enter the emitter in 2 μs,
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The distance travelled by an object along a straight line in time t is given by
- Two point objects of masses 1.5 g and 2.5 g respectively are at a distance of 16 cm
- Fusion reaction takes place at high temperature because
- In cyclotron, for a given magnet, radius of the semicircle traced by positive ion
- In a n-p-n transistor about 10¹⁰ electrons enter the emitter in 2 μs,
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply