| ⇦ | 
| ⇨ |
If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
Options
(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032
Correct Answer:
0.0164
Explanation:
Here μᵥ=1.5230and μʀ=1.5145
Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187
Now, dispersive power, ω is given by,
ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164
Related Questions: - At what temperature will the rms speed of air molecules be double that of NTP?
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
- A block of wood weighs 10 N and is resting on an inclined plane. The coefficient
- The wavelength of X-rays is in the range
- The upper half of an inclined plane of inclination θ is perfectly smooth while lower
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- At what temperature will the rms speed of air molecules be double that of NTP?
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
- A block of wood weighs 10 N and is resting on an inclined plane. The coefficient
- The wavelength of X-rays is in the range
- The upper half of an inclined plane of inclination θ is perfectly smooth while lower
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply