| ⇦ |
| ⇨ |
Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å. Number of spectral lines in the resulting spectrum emitted will be
Options
(a) 3
(b) 2
(c) 6
(d) 10
Correct Answer:
6
Explanation:
For the λ=975 Å
1 / λ = R [(1/n₁²) – (1/n₂²)]
where R is the Rydberg constant
Solving we get n₂ = n = 4 (Since, n₁ = 1 ground state)
Therefore number of spectral lines = n(n – 1) / 2 = 4(4 – 1) / 2 = 6.
Related Questions: - A layer of glycerine of thickness 1 mm present between a large surface area of 0.1 m².
- Two closed pipes produce 10 beats per second when emitting their fundamental nodes.
- A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats
- Two solid discs of radii r and 2r roll from the top of an inclined plane
- A solid sphere is rotating in free space.If the radius of the sphere is increased
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A layer of glycerine of thickness 1 mm present between a large surface area of 0.1 m².
- Two closed pipes produce 10 beats per second when emitting their fundamental nodes.
- A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats
- Two solid discs of radii r and 2r roll from the top of an inclined plane
- A solid sphere is rotating in free space.If the radius of the sphere is increased
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply