| ⇦ | 
| ⇨ |
Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å. Number of spectral lines in the resulting spectrum emitted will be
Options
(a) 3
(b) 2
(c) 6
(d) 10
Correct Answer:
6
Explanation:
For the λ=975 Å
1 / λ = R [(1/n₁²) – (1/n₂²)]
where R is the Rydberg constant
Solving we get n₂ = n = 4 (Since, n₁ = 1 ground state)
Therefore number of spectral lines = n(n – 1) / 2 = 4(4 – 1) / 2 = 6.
Related Questions: - Two 220V – 100W bulbs are connected first in series and then in parallel.
- Time taken by light to cross a glass slab of thickness 4 mm and refractive index 3 is
- Two closed organ pipes when sounded simultaneously give 4 beats/second.
- An inductor 20 mH, a capacitor 50 μF and a resistor 40Ω are connected in series
- Order of e/m ratio of proton, α-particle and electron is
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two 220V – 100W bulbs are connected first in series and then in parallel.
- Time taken by light to cross a glass slab of thickness 4 mm and refractive index 3 is
- Two closed organ pipes when sounded simultaneously give 4 beats/second.
- An inductor 20 mH, a capacitor 50 μF and a resistor 40Ω are connected in series
- Order of e/m ratio of proton, α-particle and electron is
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply