| ⇦ | 
| ⇨ |
Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å. Number of spectral lines in the resulting spectrum emitted will be
Options
(a) 3
(b) 2
(c) 6
(d) 10
Correct Answer:
6
Explanation:
For the λ=975 Å
1 / λ = R [(1/n₁²) – (1/n₂²)]
where R is the Rydberg constant
Solving we get n₂ = n = 4 (Since, n₁ = 1 ground state)
Therefore number of spectral lines = n(n – 1) / 2 = 4(4 – 1) / 2 = 6.
Related Questions: - What should be the velocity(v) of a sound source moving towards a stationary observer
- Length of second pendulum is
- A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature
- For a cubic crystal structure which one of the following relations
- For a transformer, the turns ratio is 3 and its efficiency is 0.75. The current flowing
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What should be the velocity(v) of a sound source moving towards a stationary observer
- Length of second pendulum is
- A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature
- For a cubic crystal structure which one of the following relations
- For a transformer, the turns ratio is 3 and its efficiency is 0.75. The current flowing
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply