⇦ | ⇨ |
How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide
Options
(a) 1
(b) 2
(c) 3
(d) 4
Correct Answer:
3
Explanation:
Iodine is liberated from potassium iodide.
K₂Cr₂O₇ + 4H₂SO₄ → K₂ SO₄+ Cr₂(SO₄)₃ + 4H₂O+ 3[O]
[2KI + H₂SO₄+[O] → K₂ SO₄ + I₂ +H₂O] ⨯ 3 /
[ K₂Cr₂O₇ + 6KI + 7H₂ SO₄ → 4K₂ SO₄+ Cr₂(SO₄)₃ + 7H₂O + 3I₂].
Related Questions: - For a reaction , 2NOCl(g) ⇌ 2NO(g) + Cl₂(g), Kc at 427⁰C
- The metal-carbon bond in metal carbonyl possesses
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
- Equivalent weight of KMnO₄ in basic medium is (mol.wt. of KMnO₄ = 158)
- 1-bromopropane on treatment with ethanolic potassium hydroxide produces
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a reaction , 2NOCl(g) ⇌ 2NO(g) + Cl₂(g), Kc at 427⁰C
- The metal-carbon bond in metal carbonyl possesses
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
- Equivalent weight of KMnO₄ in basic medium is (mol.wt. of KMnO₄ = 158)
- 1-bromopropane on treatment with ethanolic potassium hydroxide produces
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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