| ⇦ | 
| ⇨ |
How many coulombs are required for the oxidation of 1 mole H₂O to O₂
Options
(a) 3.86 x 10⁵ C
(b) 1.93 x 10⁵ C
(c) 4.825 x 10⁴ C
(d) 9.65 x 10⁴ C
Correct Answer:
1.93 x 10⁵ C
Explanation:
H₂O → H₂ + 1/2 O₂ mole. No. of electrons involved = 2 mole = 2 × 6.023 × 10²³. 1 mole of electronic charge = 96500 C. ⇒ 2 mole of electronic charge = 2 × 96500. = 1.93 × 10⁵ C.
Related Questions: - Platinum, palladium and iridium are called noble metals because
- Complexes with bidentate ligands are called
- The ligand N(CH₂CH₂NH₂)₃ is
- Chlorine is in +1 oxidation state in which of the following
- A device that converts energy of combustion of fuels like hydrogen and methane,
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Platinum, palladium and iridium are called noble metals because
- Complexes with bidentate ligands are called
- The ligand N(CH₂CH₂NH₂)₃ is
- Chlorine is in +1 oxidation state in which of the following
- A device that converts energy of combustion of fuels like hydrogen and methane,
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply