⇦ | ⇨ |
How many coulombs are required for the oxidation of 1 mole H₂O to O₂
Options
(a) 3.86 x 10⁵ C
(b) 1.93 x 10⁵ C
(c) 4.825 x 10⁴ C
(d) 9.65 x 10⁴ C
Correct Answer:
1.93 x 10⁵ C
Explanation:
H₂O → H₂ + 1/2 O₂ mole. No. of electrons involved = 2 mole = 2 × 6.023 × 10²³. 1 mole of electronic charge = 96500 C. ⇒ 2 mole of electronic charge = 2 × 96500. = 1.93 × 10⁵ C.
Related Questions: - Main constituents of LPG is
- On electrolysis of dilute H₂SO₄ using plantinum electrodes , the gas evolved at
- After tow hours, the ratioactive substance becomes 1/16th of original amount
- Hydro-metallurgical process of extraction of metals is based on
- ‘Metals are usually not found as nitrates in their ores”. Out of the following two
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Main constituents of LPG is
- On electrolysis of dilute H₂SO₄ using plantinum electrodes , the gas evolved at
- After tow hours, the ratioactive substance becomes 1/16th of original amount
- Hydro-metallurgical process of extraction of metals is based on
- ‘Metals are usually not found as nitrates in their ores”. Out of the following two
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply