| ⇦ | 
| ⇨ |
How many coulombs are required for the oxidation of 1 mole H₂O to O₂
Options
(a) 3.86 x 10⁵ C
(b) 1.93 x 10⁵ C
(c) 4.825 x 10⁴ C
(d) 9.65 x 10⁴ C
Correct Answer:
1.93 x 10⁵ C
Explanation:
H₂O → H₂ + 1/2 O₂ mole. No. of electrons involved = 2 mole = 2 × 6.023 × 10²³. 1 mole of electronic charge = 96500 C. ⇒ 2 mole of electronic charge = 2 × 96500. = 1.93 × 10⁵ C.
Related Questions: - Benzaldehyde can be prepared by the hydrolysis of
- An emulsion is a colloidal dispersion of
- ³⁵₁₇Cl and ³⁷₁₇Cl are two isotopes of chlorine. If average atomic weight is 35.5
- K₃Fe(CN)₆ + e⁻ → K₄Fe(CN)₆ is known as
- Pyrolusite is an ore of
Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Benzaldehyde can be prepared by the hydrolysis of
- An emulsion is a colloidal dispersion of
- ³⁵₁₇Cl and ³⁷₁₇Cl are two isotopes of chlorine. If average atomic weight is 35.5
- K₃Fe(CN)₆ + e⁻ → K₄Fe(CN)₆ is known as
- Pyrolusite is an ore of
Topics: Electrochemistry and Chemical Kinetics (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply