| ⇦ | 
| ⇨ |
How many calories are required to heat 40 gram of argon from 40⁰C to 100⁰C at constant volume? ( R = 2 cal/mol.K)
Options
(a) 120
(b) 2400
(c) 1200
(d) 180
Correct Answer:
180
Explanation:
The molar heat capacity is the heat required to raise the temperature of one mole of the gas by 1°C.
Molar heat capacity at constant volume : C(v) = (3 / 2) R
40 gram of argon means 1 mole.
Here, C(v) = 3 cal
Thus the heat required to raise the temperature by 60°C is
60 × 3 = 180 cal.
Related Questions: - A secondary amine could be prepared readily from the starting material
- Gadolinium belongs to 4f series. Its atomic number is 64
- The types of bond present in CuSO₄.5H₂O are only
- HgI₂ reacts KI in aqueous solution to form K₂HgI₄.If small amount of HgI₂
- Which one of the following has an aromatic character
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A secondary amine could be prepared readily from the starting material
- Gadolinium belongs to 4f series. Its atomic number is 64
- The types of bond present in CuSO₄.5H₂O are only
- HgI₂ reacts KI in aqueous solution to form K₂HgI₄.If small amount of HgI₂
- Which one of the following has an aromatic character
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply