| ⇦ |
| ⇨ |
Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line of the Balmer series in hydrogen spectrum will be
Options
(a) 0.5×10⁷ m⁻¹
(b) 0.25×10⁷ m⁻¹
(c) 2.5×10⁷ m⁻¹
(d) 0.025×10⁷ m⁻¹
Correct Answer:
0.25×10⁷ m⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A 0.01 H inductor and √3 πΩ resistance are connected in series
- In a uniform circular motion, work done in one complete rotation is
- Two satellites of earth, S₁ and S₂ are moving in the same orbit. The mass of S₁
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- If the value of potential in an A.C circuit is 10 V, the peak value of potential is
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A 0.01 H inductor and √3 πΩ resistance are connected in series
- In a uniform circular motion, work done in one complete rotation is
- Two satellites of earth, S₁ and S₂ are moving in the same orbit. The mass of S₁
- A thin circular ring of mass M and radius R is rotating in a horizontal plane about
- If the value of potential in an A.C circuit is 10 V, the peak value of potential is
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply