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Four cells, each of emf E and internal resistance r, are connected in series across an external resistance R. By mistake one of the cells is connected in reverse. Then, the current in the external circuit is
Options
(a) 2E/4r+R
(b) 3E/4r+R
(c) 3E/3r+R
(d) 2E/3r+R
Correct Answer:
2E/4r+R
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In L-C-R series circuit, an alternating emf e and current i are given by the equations
- Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- The ratio of specific charge of an α-particle to that of a proton is
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
- The current in a conductor varies with time t as I=2t+3t² Where I is in amperes
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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