| ⇦ | 
| ⇨ |
For the reversible reaction ,
N₂(g) + 3H₂(g) ⇌ 2NH₃(g) + heat
The equilibrium shifts in forward direction
Options
(a) by increasing the concentration of NH₃(g)
(b) by decreasing the pressure
(c) by decreasing the concentration of N₂(g) and H₂(g)
(d) by increasing pressure and decreasing temperature
Correct Answer:
by increasing pressure and decreasing temperature
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Standard enthalpy of vaporisation Δvap H⁰ for water at 100⁰C is 40.66 kJ mol⁻¹.
- The heat of neutralization of a strong base and a strong acid is 57 kJ.
- The correct order of electron affinity is
- Which one of the following reagents will be able to distinguish between 1-butyne
- Rate determining step in nitration of bezene is
Topics: Equilibrium
(104)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Standard enthalpy of vaporisation Δvap H⁰ for water at 100⁰C is 40.66 kJ mol⁻¹.
- The heat of neutralization of a strong base and a strong acid is 57 kJ.
- The correct order of electron affinity is
- Which one of the following reagents will be able to distinguish between 1-butyne
- Rate determining step in nitration of bezene is
Topics: Equilibrium (104)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply