For the equilibrium, H₂O(l) ⇌ H₂O(g) at 1 atm and 298 K,

For The Equilibrium Hol Hog At 1 Atm And Chemistry Question

For the equilibrium, H₂O(l) ⇌ H₂O(g) at 1 atm and 298 K,

Options

(a) standard free energy change is equal to zero (ΔG⁰ = 0)
(b) free energy change is less then zero (ΔG⁰ < 0)
(c) standard free energy change is less then zero (ΔG⁰ < 0)
(d) standard free energy change is greater then zero (ΔG⁰ > 0)

Correct Answer:

free energy change is less then zero (ΔG⁰ < 0)

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. HSO₄⁻ + OH⁻ → SO₄²⁻ + H₂O. which is correct about conjugate acid – base pair
  2. Formalin is a
  3. 1 c.c N₂O at NTP contains
  4. The reaction CH₃ – Br + 2Na + Br – CH₃ → CH₃ – CH₃ is called
  5. 20.0 g of a magnesium carbonate sample decomposes on heating to give carbon dioxide

Topics: Equilibrium (104)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*