⇦ | ⇨ |
Equivalent weight of KMnO₄ in basic medium is (mol.wt. of KMnO₄ = 158)
Options
(a) 31.5
(b) 52.67
(c) 79
(d) 158
Correct Answer:
52.67
Explanation:
MnO₄⁻ + 2H₂O + 3e⁻ → MnO₂ + 4OH⁻
Equivalent weight = molecular weight / 3.
The oxidation number changes from +7 to +4. so , Equivalent weight = 158/3 = 52.67.
Related Questions: - The oxidation number of xenon in XeOF₂ is
- Which of the following corresponds to the electronic configuration 1s², 2s²,2p⁶
- The oxidation number of oxygen in O₂PtF₆ is
- Which one of the following is an example of thermosetting polymer
- A sp³ – hybrid orbital contains
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The oxidation number of xenon in XeOF₂ is
- Which of the following corresponds to the electronic configuration 1s², 2s²,2p⁶
- The oxidation number of oxygen in O₂PtF₆ is
- Which one of the following is an example of thermosetting polymer
- A sp³ – hybrid orbital contains
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply