| ⇦ |
| ⇨ |
Equal volumes of methanoic acid and sodium hydroxide are mixed, if x is the heat of formation of water, then heat evolved on neutralisation is
Options
(a) twice of x
(b) equal to x
(c) more than x
(d) less than x
Correct Answer:
less than x
Explanation:
“Methanoic acid(HCOOH), Sodium hydroxide(NaOH). Weak acid and strong base neutralisation. H⁺ + OH⁻ → H₂O + x(Heat of formation),
HCOOH ⇌ HCOO⁻ + H⁺, NaOH ⇌ Na⁺ + OH⁻,
H⁺ + OH⁻ ⇌ H₂O + Less than x (Heat of reaction). Because, some of the energy is lost in ionization of weak acid, HCOOH.”.
Related Questions: - 1,1,2,2-tetrabromoethane on treatment with Zn dust yields an
- Carbohydrates are stored in human body as the polysaccharide
- Which of the following will exhibit maximum ionic conductivity?
- Ionisation constant of CH₃COOH is 1.7 ˣ 10⁻⁵ and concentration of H⁺ ions
- Which among the following is strong acid
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 1,1,2,2-tetrabromoethane on treatment with Zn dust yields an
- Carbohydrates are stored in human body as the polysaccharide
- Which of the following will exhibit maximum ionic conductivity?
- Ionisation constant of CH₃COOH is 1.7 ˣ 10⁻⁵ and concentration of H⁺ ions
- Which among the following is strong acid
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply