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Equal volumes of methanoic acid and sodium hydroxide are mixed, if x is the heat of formation of water, then heat evolved on neutralisation is
Options
(a) twice of x
(b) equal to x
(c) more than x
(d) less than x
Correct Answer:
less than x
Explanation:
“Methanoic acid(HCOOH), Sodium hydroxide(NaOH). Weak acid and strong base neutralisation. H⁺ + OH⁻ → H₂O + x(Heat of formation),
HCOOH ⇌ HCOO⁻ + H⁺, NaOH ⇌ Na⁺ + OH⁻,
H⁺ + OH⁻ ⇌ H₂O + Less than x (Heat of reaction). Because, some of the energy is lost in ionization of weak acid, HCOOH.”.
Related Questions: - Carbon percentage is maximum in
- Equal masses of H₂, O₂ and methane have been taken in a container of volume
- The long form of periodic table is based on
- The strongest conjugate base is
- The oxidation number of As in H₂AsO₄⁻ is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Carbon percentage is maximum in
- Equal masses of H₂, O₂ and methane have been taken in a container of volume
- The long form of periodic table is based on
- The strongest conjugate base is
- The oxidation number of As in H₂AsO₄⁻ is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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