| ⇦ |
| ⇨ |
Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric field is
Options
(a) 3 √2
(b) 4 √2
(c) 5 √2
(d) 7
Correct Answer:
7
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A force of 5 N is acting on an object. Displacement of object is 10 m and the work done
- Ratio of the radii of the nuclei with mass numbers 8 and 27 would be
- The order of distance of an electron revolving in an atom from nucleus is
- Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A force of 5 N is acting on an object. Displacement of object is 10 m and the work done
- Ratio of the radii of the nuclei with mass numbers 8 and 27 would be
- The order of distance of an electron revolving in an atom from nucleus is
- Hydrogen atom in ground state is excited by a monochrmatic radiation of λ=975 Å
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply