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Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric field is
Options
(a) 3 √2
(b) 4 √2
(c) 5 √2
(d) 7
Correct Answer:
7
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The current flowing through a lamp marked as 50 W and 250 V is
- Two identical circular coils A and B are kept on a horizontal tube
- A particle is executing the motion x=Acos (ωt-θ). The maximum velocity of the particle is
- The current in the windings of a toroid is 2.0 A. There are 400 turns
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Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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