⇦ | ⇨ |
Decreasing order of stability of O₂ , O₂⁻ , O₂⁺ and O₂²⁻ is
Options
(a) O₂²⁻ > O₂⁻ > O₂ >O₂⁺
(b) O₂> O₂⁺ > O₂²⁻ > O₂⁻
(c) O₂⁻ > O₂²⁻ > O₂⁺ >O₂
(d) O₂⁺ > O₂ > O₂⁻ > O₂²⁻
Correct Answer:
O₂⁺ > O₂ > O₂⁻ > O₂²⁻
Explanation:
According to molecular orbital theory as bond order decreases stability of the molecule decreases
Bond order =1/2 (N(b)-N(a))
Bond order for O₂⁺=1/2 (10-5)=2.5
Bond order for O₂=1/2 (10-6)=2
Bond order for O₂⁻=1/2 (10-7)=1.5
Bond order for O₂²⁻=1/2 (10-8)=1.0
hence the correct order is
O₂⁺ > O₂ > O₂⁻> O₂²⁻
Related Questions: - Which one of the following statements about the nitro group in organic compound
- n-Butane and isobutane are
- Which ion is detected by Nessler’s reagent
- Which of the following is not a common component of Photochemical Smong
- Excess of Na⁺ ions in air system causes
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following statements about the nitro group in organic compound
- n-Butane and isobutane are
- Which ion is detected by Nessler’s reagent
- Which of the following is not a common component of Photochemical Smong
- Excess of Na⁺ ions in air system causes
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply