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CuSO₄ dissolves in NH₃ due to the formation of
Options
(a) Cu(OH)₂
(b) Cu[(NH₃)₄]SO₄
(c) Cu[(NH₃)₄(OH)₂]
(d) CuO
Correct Answer:
Cu[(NH₃)₄(OH)₂]
Explanation:
NH₃+ H₂O→ NH₄OH
CuSO₄ + NH₄OH → Cu(OH)₂ + (NH₄)₂ SO₄ / Cu(OH)₂ + 2NH₄OH + (NH₄)₂ SO₄ → [Cu (NH₂)₄] SO₄ + 4 H₂O ( Tetrammine cupric sulphate
The complex is called as Schotzer’s reagent which is used for dissolving cellulose in the manufacture of artificial silk.
Related Questions: - Distribution law was given by
- The mixture of n-hexane and n-heptane is an example of
- The ion which is not tetrahedral in shape is
- The number of chloride ion produced by complex tetraamminedichloroplatinum(IV)
- Number of chloride ions around a single sodium ion in NaCl crystal is
Topics: Coordination Compounds
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Distribution law was given by
- The mixture of n-hexane and n-heptane is an example of
- The ion which is not tetrahedral in shape is
- The number of chloride ion produced by complex tetraamminedichloroplatinum(IV)
- Number of chloride ions around a single sodium ion in NaCl crystal is
Topics: Coordination Compounds (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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