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CuSO₄ dissolves in NH₃ due to the formation of
Options
(a) Cu(OH)₂
(b) Cu[(NH₃)₄]SO₄
(c) Cu[(NH₃)₄(OH)₂]
(d) CuO
Correct Answer:
Cu[(NH₃)₄(OH)₂]
Explanation:
NH₃+ H₂O→ NH₄OH
CuSO₄ + NH₄OH → Cu(OH)₂ + (NH₄)₂ SO₄ / Cu(OH)₂ + 2NH₄OH + (NH₄)₂ SO₄ → [Cu (NH₂)₄] SO₄ + 4 H₂O ( Tetrammine cupric sulphate
The complex is called as Schotzer’s reagent which is used for dissolving cellulose in the manufacture of artificial silk.
Related Questions: - Decreasing order of nucleophilicity is
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- The range of radius ratio (cationic to anionic) for an octahedral arrangement
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Topics: Coordination Compounds
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Decreasing order of nucleophilicity is
- Gem-dihalides are hydrolysed with either acid or basic catalysts to give
- The range of radius ratio (cationic to anionic) for an octahedral arrangement
- Amount of calcium oxide required, when it reacts with 852 g of P₄O₁₀ is
- Which of the following is not an actinide
Topics: Coordination Compounds (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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