| ⇦ |
| ⇨ |
Crystal field stabilization energy for high spin d⁴ octahedral complex is
Options
(a) -1.8 Δ₀
(b) -1.6 Δ₀ + P
(c) -1.2 Δ₀
(d) -0.6 Δ₀
Correct Answer:
-0.6 Δ₀
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The coordination number and oxidation number of X in the following compound [X(SO₄)(NH₃)₅]Cl
- The correct order of increasing bond length of C–H, C–O, C–C and C=C is
- Which is the amount of chlorine evolved when 2 amperes of current is passed for
- The strongest reducing agent is
- Which of the following metals reacts with water
Topics: Coordination Compounds
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The coordination number and oxidation number of X in the following compound [X(SO₄)(NH₃)₅]Cl
- The correct order of increasing bond length of C–H, C–O, C–C and C=C is
- Which is the amount of chlorine evolved when 2 amperes of current is passed for
- The strongest reducing agent is
- Which of the following metals reacts with water
Topics: Coordination Compounds (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply