| ⇦ | 
| ⇨ |
Consider 3rd orbit of He⁺(helium), using non-relativistic approach, the speed of electron in this orbit will be (given K=9×10⁹ constant, Z=2 and h=6.6×10⁻³⁴ J-s)
Options
(a) 2.92×10⁶ ms⁻¹
(b) 1.46×10⁶ ms⁻¹
(c) 0.73×10⁶ ms⁻¹
(d) 3×10⁶ ms⁻¹
Correct Answer:
1.46×10⁶ ms⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A bar magnet has a coercivity of 4×10³ Am⁻¹. It is placed inside a solenoid
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- Heat is flowing through a rod of length 50 cm and area of cross-section 5 cm².
- The half life of a radioactive isotope ‘X’ is 20 years. It decays to another element Y
- The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bar magnet has a coercivity of 4×10³ Am⁻¹. It is placed inside a solenoid
- A ray enters a glass sphere of refractive index μ=√3 at an angle of incidence of 60⁰
- Heat is flowing through a rod of length 50 cm and area of cross-section 5 cm².
- The half life of a radioactive isotope ‘X’ is 20 years. It decays to another element Y
- The horizontal component of earth’s magnetic field at a place is 3×10⁻⁴ T
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply