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Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the centre of the ring is
Options
(a) µ₀q f / 2 R
(b) µ₀q / 2 f R
(c) µ₀q / 2π f R
(d) µ₀q f / 2π R
Correct Answer:
µ₀q f / 2 R
Explanation:
When the ring rotates f Hz, the current flowing in the ring is i = q/T = qf
Magnetic field at the centre of the ring is
B = µ₀I / 2 R = µ₀q f / 2 R
Related Questions: - Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
- A proton and helium nucleus are shot into a magnetic field at right angles to the field
- Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
- In Moseley’s law √ν=a(z-b), the values of the screening constant for K-series
- A coil of 100 turns carries a current of 5 mA and creates a magnetic flux of 10⁻⁵ Wb.
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Thomson coefficient of a conductor is 10 µV/K. Its two ends are kept
- A proton and helium nucleus are shot into a magnetic field at right angles to the field
- Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
- In Moseley’s law √ν=a(z-b), the values of the screening constant for K-series
- A coil of 100 turns carries a current of 5 mA and creates a magnetic flux of 10⁻⁵ Wb.
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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