| ⇦ |
| ⇨ |
Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the centre of the ring is
Options
(a) µ₀q f / 2 R
(b) µ₀q / 2 f R
(c) µ₀q / 2π f R
(d) µ₀q f / 2π R
Correct Answer:
µ₀q f / 2 R
Explanation:
When the ring rotates f Hz, the current flowing in the ring is i = q/T = qf
Magnetic field at the centre of the ring is
B = µ₀I / 2 R = µ₀q f / 2 R
Related Questions: - The depletion layer in the p-n junction region is caused by
- The intermediate image formed by the objective of a compound microscope is
- In which of the following heat loss is primarily not due to convection?
- The radius of a ball is(5.2±0.2)cm.The percentage error in the volume of the ball
- In the equation y=asin(?t+kx),the dimensionals formula of ? is
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The depletion layer in the p-n junction region is caused by
- The intermediate image formed by the objective of a compound microscope is
- In which of the following heat loss is primarily not due to convection?
- The radius of a ball is(5.2±0.2)cm.The percentage error in the volume of the ball
- In the equation y=asin(?t+kx),the dimensionals formula of ? is
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply