| ⇦ | 
| ⇨ |
Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the centre of the ring is
Options
(a) µ₀q f / 2 R
(b) µ₀q / 2 f R
(c) µ₀q / 2π f R
(d) µ₀q f / 2π R
Correct Answer:
µ₀q f / 2 R
Explanation:
When the ring rotates f Hz, the current flowing in the ring is i = q/T = qf
Magnetic field at the centre of the ring is
B = µ₀I / 2 R = µ₀q f / 2 R
Related Questions: - An air core coil and an electric bulb are connected in series with an AC source.
- When current I is flowing through a conductor, the drift velocity is v.
- A body travels 200 cm in the first two seconds and 220 cm in the next 4 secs
- The difference in the variation of resistance with temperature in a metal
- A series L-C-R circuit contains inductance 5 mH, capacitance 2 μF and resistance
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An air core coil and an electric bulb are connected in series with an AC source.
- When current I is flowing through a conductor, the drift velocity is v.
- A body travels 200 cm in the first two seconds and 220 cm in the next 4 secs
- The difference in the variation of resistance with temperature in a metal
- A series L-C-R circuit contains inductance 5 mH, capacitance 2 μF and resistance
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply