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Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the centre of the ring is
Options
(a) µ₀q f / 2 R
(b) µ₀q / 2 f R
(c) µ₀q / 2π f R
(d) µ₀q f / 2π R
Correct Answer:
µ₀q f / 2 R
Explanation:
When the ring rotates f Hz, the current flowing in the ring is i = q/T = qf
Magnetic field at the centre of the ring is
B = µ₀I / 2 R = µ₀q f / 2 R
Related Questions: - A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
- An air core coil and an electric bulb are connected in series with an AC source.
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- Alternating current cannot be measured by D.C Ammeter because
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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