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Charge q is uniformly spread on a thin ring of radius R. The ring rotates about its axis with a uniform frequency f Hz. The magnitude of magnetic induction at the centre of the ring is
Options
(a) µ₀q f / 2 R
(b) µ₀q / 2 f R
(c) µ₀q / 2π f R
(d) µ₀q f / 2π R
Correct Answer:
µ₀q f / 2 R
Explanation:
When the ring rotates f Hz, the current flowing in the ring is i = q/T = qf
Magnetic field at the centre of the ring is
B = µ₀I / 2 R = µ₀q f / 2 R
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a gymnast, sitting on a rotating stool with his arms outstretched, suddenly
- The half-life of a radioactive substance is 30 min. The time (in minutes) taken
- Suppose for some reasons, radius of earth were to shrink by 1% of present value,
- At what height h above earth, the value of g becomes g/2 (where R=radius of earth)?
- A thin semicircular conducting ring (PQR) of radius r is falling with its plane
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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