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Calculate the amount of [Ca(OH)₂] required to remove the hardness of water from 60,000 litres containing 16.2 g of Ca(HCO₃)₂ per 100 litre
Options
(a) 1.11 kg
(b) 2.22 kg
(c) 3.33 kg
(d) 4.44 kg
Correct Answer:
4.44 kg
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The percentage weight of Zn in white vitriol [ZnSO₄ 7H₂O] is approximately equal
- In the following reaction reducing agent is
2K₃[Fe(CN)₆]+H₂O₂+2KOH→2K₄[Fe(CN)₆]
- In the reaction of phenol with CHCl₃ and aq.KOH the electrophile attacking
- In an SN1 reaction on chiral centres there is
- Which contains both polar and non-polar covalent bonds?
Topics: Hydrogen and Redox Reactions
(174)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The percentage weight of Zn in white vitriol [ZnSO₄ 7H₂O] is approximately equal
- In the following reaction reducing agent is 2K₃[Fe(CN)₆]+H₂O₂+2KOH→2K₄[Fe(CN)₆]
- In the reaction of phenol with CHCl₃ and aq.KOH the electrophile attacking
- In an SN1 reaction on chiral centres there is
- Which contains both polar and non-polar covalent bonds?
Topics: Hydrogen and Redox Reactions (174)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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