| ⇦ |
| ⇨ |
Bond order of 1.5 is shown by:
Options
(a) O₂⁺
(b) O₂⁻
(c) O₂²⁻
(d) O₂⁻
Correct Answer:
O₂⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Cell reaction is spontaneous when
- A dibromo derivative of an alkane reacts with sodium metal to form an alicyclic
- H₂O₂ reduces MnO₄⁻ ion to
- Planar structure is shown by
- The total number of atomic orbitals in fourth energy level of an atom is :
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Cell reaction is spontaneous when
- A dibromo derivative of an alkane reacts with sodium metal to form an alicyclic
- H₂O₂ reduces MnO₄⁻ ion to
- Planar structure is shown by
- The total number of atomic orbitals in fourth energy level of an atom is :
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply