⇦ | ⇨ |
Bond order of 1.5 is shown by:
Options
(a) O₂⁺
(b) O₂⁻
(c) O₂²⁻
(d) O₂⁻
Correct Answer:
O₂⁻
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The conductivity of strong electrolyte
- The number of d-electrons in Fe²⁺(Z=26) is not equal to the number of electrons
- The number of primary, secondary and tertiary carbons in 3,4-dimethylheptane
- Milk is an emulsion of
- If 1 litre of N₂ is mixed with 2 litre of O₂, quantity explaining it is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Chemical Bonding and Molecular Structure
(86)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The conductivity of strong electrolyte
- The number of d-electrons in Fe²⁺(Z=26) is not equal to the number of electrons
- The number of primary, secondary and tertiary carbons in 3,4-dimethylheptane
- Milk is an emulsion of
- If 1 litre of N₂ is mixed with 2 litre of O₂, quantity explaining it is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Chemical Bonding and Molecular Structure (86)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply