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At S.T.P the density of CCl₄ vapours in g/L will be nearest to
Options
(a) 6.87
(b) 3.42
(c) 10.26
(d) 4.57
Correct Answer:
6.87
Explanation:
Molecular Weight of CCl₄ = 35.5 + 12 x 4 = 154
1 mole CCl₄ vapour=154 g
According to Avogadro’s hypothesis we know that the molar volume of a gas at STP is 22.4 litres
= 154/22.4 = 6.87
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Calculate the amount of [Ca(OH)₂] required to remove the hardness of water
- Main constituents of LPG is
- ‘The addition of unsymmetrical reagents to unsymmetrical alkenes occurs in such
- Equivalent weight of KMnO₄ in basic medium is (mol.wt. of KMnO₄ = 158)
- One litre hard water contains 12 mg Mg²⁺. Milli equivalents of washing soda
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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