⇦ | ![]() | ⇨ |
At S.T.P the density of CCl₄ vapours in g/L will be nearest to
Options
(a) 6.87
(b) 3.42
(c) 10.26
(d) 4.57
Correct Answer:
6.87
Explanation:
Molecular Weight of CCl₄ = 35.5 + 12 x 4 = 154
1 mole CCl₄ vapour=154 g
According to Avogadro’s hypothesis we know that the molar volume of a gas at STP is 22.4 litres
= 154/22.4 = 6.87
Related Questions:
- Which of the following is an amphoteric oxide
- Which of the following C-H bonds has lowest bond dissociation energy
- Diazo-coupling is useful to prepare some
- A bivalent metal has the equivalent weight of 12. The molecular weight
- An isocyanide on hydrolysis gives
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply