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At place on earth, the vertical component of earth’s magnetic field is √3 times its horizontal component. The angle of dip at this place is …….
Options
(a) 60⁰
(b) 30⁰
(c) 45⁰
(d) 0⁰
Correct Answer:
60⁰
Explanation:
As vertical component of Earth’s magnetic field is Bᵥ = √3 Bʜ
Angle of dip at any place is a given by, tan δ = Bᵥ / Bʜ = Bᵥ = √3 Bʜ / Bʜ = √3
Then, δ = tan⁻¹ (√3) = 60⁰
Related Questions: - Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- If a mass of 20g having charge 3.0 mC moving with velocity 20ms⁻¹ enters a region
- A stone of mass 1kg is tied to a string 4m long and is rotated at constant speed
- A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
- Length of a string tied to two rigid supports is 40 cm. Maximum length
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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