⇦ | ⇨ |
At 298 K the enthalpy of formation of liquid water is -285.9 kJ/mol and that of steam -242.8 kJ/mol. The enthalpy of vapourisation of water is
Options
(a) 43.1 kJ/mol
(b) -43.1 kJ/mol
(c) 242.8 kJ/mol
(d) -242.8 kJ/mol
Correct Answer:
43.1 kJ/mol
Explanation:
ΔH(vap) = -242.8 – (-285.9) = 43.1 kJ/mol.
Related Questions: - Which of the following substances is used, in laboratory
- The ratio of the difference in energy between first and second Bohr orbit
- What is formed when formaldehyde reacts with KOH
- The mole heat capacity of water at constant pressure, C, is 75 J K⁻¹mol⁻¹.
- Carborundum is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following substances is used, in laboratory
- The ratio of the difference in energy between first and second Bohr orbit
- What is formed when formaldehyde reacts with KOH
- The mole heat capacity of water at constant pressure, C, is 75 J K⁻¹mol⁻¹.
- Carborundum is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply