| ⇦ | 
| ⇨ |
At 298 K the enthalpy of formation of liquid water is -285.9 kJ/mol and that of steam -242.8 kJ/mol. The enthalpy of vapourisation of water is
Options
(a) 43.1 kJ/mol
(b) -43.1 kJ/mol
(c) 242.8 kJ/mol
(d) -242.8 kJ/mol
Correct Answer:
43.1 kJ/mol
Explanation:
ΔH(vap) = -242.8 – (-285.9) = 43.1 kJ/mol.
Related Questions: - If the enthalpy change for the transition of liquid water to steam
- Kinetic theory of gases presumes that collision between the molecules to be perfectly
- Bauxite is concentrated by
- NaHCO₃ is prepared by
- Number of orbitals present in 3rd shell is
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the enthalpy change for the transition of liquid water to steam
- Kinetic theory of gases presumes that collision between the molecules to be perfectly
- Bauxite is concentrated by
- NaHCO₃ is prepared by
- Number of orbitals present in 3rd shell is
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply