At 27⁰C average kinetic energy of one mole of helium gas can be given

At 27c Average Kinetic Energy Of One Mole Of Helium Chemistry Question

At 27⁰C average kinetic energy of one mole of helium gas can be given

Options

(a) 3741.30 J mol⁻¹
(b) 374.13 J mol⁻¹
(c) 1662.8 J mol⁻¹
(d) 166.28 J mol⁻¹

Correct Answer:

3741.30 J mol⁻¹

Explanation:

The average kinetic energy per mole does not depend on the nature of the gas but depends only on temperature. Average Kinetic energy per mole = 3 / 2 RT. given, T = 27⁰C = 273 + 27 = 300 K. R = 8.314 JK⁻¹ mol ⁻¹ ⇒ K.E = 3/2 x 8.314 x 300 = 3741.3 J mol ⁻¹.

Related Questions:

  1. Which of the following will show a negative deviation from Raoult’s law
  2. Which of the following sets of quantum numbers violates the rules of quantum mechanics
  3. The following composition is known as “Bordeaux mixture”.
  4. In graphide electrons are
  5. The correct order of electron affinity is

Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*