| ⇦ |
| ⇨ |
At 27⁰C average kinetic energy of one mole of helium gas can be given
Options
(a) 3741.30 J mol⁻¹
(b) 374.13 J mol⁻¹
(c) 1662.8 J mol⁻¹
(d) 166.28 J mol⁻¹
Correct Answer:
3741.30 J mol⁻¹
Explanation:
The average kinetic energy per mole does not depend on the nature of the gas but depends only on temperature. Average Kinetic energy per mole = 3 / 2 RT. given, T = 27⁰C = 273 + 27 = 300 K. R = 8.314 JK⁻¹ mol ⁻¹ ⇒ K.E = 3/2 x 8.314 x 300 = 3741.3 J mol ⁻¹.
Related Questions: - The activation energy of a reaction at a given temperature is found to be 2.303
- Identify the molecule that has zero dipole moment
- Isotonic solution have the same
- In the conversion of Br₂ to BrO₃⁻, the oxidation number of Br changes from
- All Cu(II) halides are known except the iodide. The reason for it is that
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The activation energy of a reaction at a given temperature is found to be 2.303
- Identify the molecule that has zero dipole moment
- Isotonic solution have the same
- In the conversion of Br₂ to BrO₃⁻, the oxidation number of Br changes from
- All Cu(II) halides are known except the iodide. The reason for it is that
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply