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Aniline is treated with a mixture of sodium nitrite and hypophosphorus acid, the product formed is
Options
(a) aniline diazonium hypophosphate
(b) benzene
(c) anilinium hypophosphite
(d) aniline diazonium hypophosphite
Correct Answer:
benzene
Explanation:
H₃PO₂ serves both as an acid as well as a reducing agent. The diazonium salt initially formed is reduced to give benzene. C₆H₅NH₂ → C₆H₅N₂⁺ HPO₂⁻ → C₆H₆ + N₂ .
Related Questions: - Which one of the following is the correct order of size of othe iodine specifies?
- Number of unpaired electrons in N2⁺ is
- The s-block element used as a catalyst in the manufacture of Buna-S rubber is
- Which of the following is a Lewis acid
- The type of hybridisation of boron in diboron is
Topics: Organic compounds containing Nitrogen
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following is the correct order of size of othe iodine specifies?
- Number of unpaired electrons in N2⁺ is
- The s-block element used as a catalyst in the manufacture of Buna-S rubber is
- Which of the following is a Lewis acid
- The type of hybridisation of boron in diboron is
Topics: Organic compounds containing Nitrogen (87)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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