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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An experiment takes 10 minutes to raise temperature of water from 0⁰C to 100⁰C
- A bucket full of water is revolved in a vertical circle of 2m
- The flux linked with a circuit is given by φ=t³+3t-7. The graph between time
- A long straight wire of radius a carries a steady current I. The current is uniformly
- A particle A suffers on oblique elastic collision with a particle B that
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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