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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂
- According to Hook’s law of elasticity, if stress is increased, the ratio of stress
- A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic
- A point charge q is placed at a distance x/2 directly above the centre of a cube
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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