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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Heat produced in a resistance according to which law?
- Three identical spheres, each of mass 3 kg are placed touching each other
- An engine is moving towards a wall with a velocity 50 ms⁻¹ emits a note of 1.2 kHz.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Heat produced in a resistance according to which law?
- Three identical spheres, each of mass 3 kg are placed touching each other
- An engine is moving towards a wall with a velocity 50 ms⁻¹ emits a note of 1.2 kHz.
- A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively
- Which is incorrect about thermal process
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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