⇦ | ⇨ |
An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is 15cm/sec and the period is 628 mili-sec. The amplitude of the motion in cm is
Options
(a) 3
(b) 2
(c) 1.5
(d) 1
Correct Answer:
1.5
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- The ratio of the numerical value of the average velocity and average speed
- If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
- If a small sphere is let fall vertically in a large quantity of still liquid of density
- The width of the diffraction band varies
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If two vectors 2i+3j+k and -4i-6j-λk are parallel to each other, then the value of λ is
- The ratio of the numerical value of the average velocity and average speed
- If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
- If a small sphere is let fall vertically in a large quantity of still liquid of density
- The width of the diffraction band varies
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Vmax=Aω A=v/ω ω=2π/T ω=2*3.14/628*10^-3 ω=10 A=15/10 A=1.5