| ⇦ | 
| ⇨ |
An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is 15cm/sec and the period is 628 mili-sec. The amplitude of the motion in cm is
Options
(a) 3
(b) 2
(c) 1.5
(d) 1
Correct Answer:
1.5
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A bubble is rising from bottom of a lake. The volume of bubble becomes
- The threshold wavelength for photoelectric emission from a material is 4800 Å.
- The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV
- A cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration
- Two charges placed in air repel each other by a force of 10⁻⁴ N. When oil is
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bubble is rising from bottom of a lake. The volume of bubble becomes
- The threshold wavelength for photoelectric emission from a material is 4800 Å.
- The binding energy per nucleon in deuterium and helium nuclei are 1.1 MeV and 7.0 MeV
- A cycle wheel of radius 4 m completes one revolution in two seconds. Then acceleration
- Two charges placed in air repel each other by a force of 10⁻⁴ N. When oil is
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Vmax=Aω A=v/ω ω=2π/T ω=2*3.14/628*10^-3 ω=10 A=15/10 A=1.5