| ⇦ | 
| ⇨ |
An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is 15cm/sec and the period is 628 mili-sec. The amplitude of the motion in cm is
Options
(a) 3
(b) 2
(c) 1.5
(d) 1
Correct Answer:
1.5
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The average power dissipated in a pure inductor is
- The length of second pendulum is 1 m on earth. If mass and diameter
- A solid sphere, a hollow sphere and a ring are released from top of an inclined
- A tube of length L is filled completely with an incompressible liquid of mass
- A juggler maintains four balls in motion,making each of them to rise
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The average power dissipated in a pure inductor is
- The length of second pendulum is 1 m on earth. If mass and diameter
- A solid sphere, a hollow sphere and a ring are released from top of an inclined
- A tube of length L is filled completely with an incompressible liquid of mass
- A juggler maintains four balls in motion,making each of them to rise
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Vmax=Aω A=v/ω ω=2π/T ω=2*3.14/628*10^-3 ω=10 A=15/10 A=1.5