| ⇦ | 
| ⇨ |
An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is 15cm/sec and the period is 628 mili-sec. The amplitude of the motion in cm is
Options
(a) 3
(b) 2
(c) 1.5
(d) 1
Correct Answer:
1.5
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A block of mass m is moving on a wedge with the acceleration aᵒ
- An alternating emf given by equation
e=300 sin[(100 π)t] V
- A magnetic force acting on a charged particle of charge -2µC in a magnetic field of 2T
- A thin convex lens of refractive index 1.5 has 20 cm focal length in air. If the lens
- B is doped in Si or Ge, then we will get
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A block of mass m is moving on a wedge with the acceleration aᵒ
- An alternating emf given by equation e=300 sin[(100 π)t] V
- A magnetic force acting on a charged particle of charge -2µC in a magnetic field of 2T
- A thin convex lens of refractive index 1.5 has 20 cm focal length in air. If the lens
- B is doped in Si or Ge, then we will get
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Vmax=Aω A=v/ω ω=2π/T ω=2*3.14/628*10^-3 ω=10 A=15/10 A=1.5