An inductor 20 mH, a capacitor 50 μF and a resistor 40Ω are connected in series

An Inductor 20 Mh A Capacitor 50 F And A Physics Question

An inductor 20 mH, a capacitor 50 μF and a resistor 40Ω are connected in series across a source of emf V=10 sin340t. The power loss in AC circuit is

Options

(a) 0.67 W
(b) o.76 W
(c) 0.89 W
(d) 0.51 W

Correct Answer:

0.51 W

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. Calculate the charge on equivalent capacitance of the conbination shown in figure
  2. In a photoelectric effect experiment, the slope of the graph between the stopping
  3. The pressure at the bottom of a tank containing a liquid does not depend on
  4. A choke is preferred to a resistance for limiting current in AC circuit because
  5. Penetrating power of X-rays does not depend on

Topics: Alternating Current (96)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*